The locus of a point equidistant from two point... - JAMB Mathematics 2008 Question
The locus of a point equidistant from two points P(6,2) and R(4,2) is a perpendicular bisector of PR passing through
A
(2, 5)
B
(5, 2)
C
(1, 0)
D
(0,1)
correct option: b
let (6, 2) be represented as (x1, y1) and (4, 2) be (x2, y2)
p(6, 2) R(4, 2)
m.p = ((\frac{x_1 + x_2}{2})) ((\frac{y_1 + y_2}{2}))
= ((\frac{6 + 4}{2}) , (\frac{2 + 2}{2}))
= ((\frac{10}{2}),(\frac{4}{2}))
= (5, 2)
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